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How do I write the four quantum numbers of an electron in Telangana 10th Physical Science, Structure of Atom?

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TS SSC Physical Science, chapter Structure of Atom. Our textbook has n, l, ml and ms, which is not there in my friend's CBSE book. I can't work out the four quantum numbers of the last electron, for example for sodium. Also how do I know 4s fills before 3d?
quantum numbersstructure of atomelectronic configurationts ssc

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Four quantum numbers describe the address of an electron in an atom. 1. Principal quantum number (n): the main shell. n = 1, 2, 3, ... The higher n is, the farther the shell from the nucleus and the higher its energy. 2. Azimuthal (angular momentum) quantum number (l): the sub-shell. l takes values 0 to (n - 1). l = 0 is s, l = 1 is p, l = 2 is d, l = 3 is f. 3. Magnetic quantum number (ml): the orbital, that is, the orientation in space. ml takes values from -l to +l, including 0. So there are (2l + 1) orbitals in a sub-shell: s has 1, p has 3, d has 5, f has 7. 4. Spin quantum number (ms): the spin of the electron, +1/2 or -1/2. One orbital holds at most 2 electrons, with opposite spins. Worked example: valence electron of sodium (Z = 11) Electronic configuration: 1s2 2s2 2p6 3s1 The last electron is in 3s: n = 3 (third shell) l = 0 (s sub-shell) ml = 0 (only one value possible when l = 0) ms = +1/2 (a single electron in the orbital is usually given +1/2) Quick check with n = 2: l can be 0 or 1, so the sub-shells are 2s and 2p. Orbitals = 1 + 3 = 4, and electrons = 4 x 2 = 8 = 2n^2. Why 4s before 3d? Use the (n + l) rule from the Aufbau principle. The sub-shell with the lower (n + l) value fills first. 4s: n + l = 4 + 0 = 4 3d: n + l = 3 + 2 = 5 So 4s fills first. If two sub-shells have the same (n + l), the one with the lower n fills first. For example, 3d (3 + 2 = 5) fills before 4p (4 + 1 = 5). Common slips: 1. Writing l = n. The largest l is n - 1, so a 2d sub-shell cannot exist. 2. Giving ml a value outside -l to +l. 3. Writing ms as +1 or -1. It is always +1/2 or -1/2.
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